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212112213002089 is a prime number
BaseRepresentation
bin110000001110101000111001…
…000110111100011101101001
31000211000201200211021021220021
4300032220321012330131221
5210300221303012031324
62031043001101400441
762451413242161601
oct6016507106743551
91024021624237807
10212112213002089
1161649314538504
121b958926b69121
1391481327b014a
143a54400689c01
15197c7d34e1ae4
hexc0ea391bc769

212112213002089 has 2 divisors, whose sum is σ = 212112213002090. Its totient is φ = 212112213002088.

The previous prime is 212112213002071. The next prime is 212112213002143. The reversal of 212112213002089 is 980200312211212.

212112213002089 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 122553756160000 + 89558456842089 = 11070400^2 + 9463533^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212112213002089 is a prime.

It is not a weakly prime, because it can be changed into another prime (212112213002189) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106056106501044 + 106056106501045.

It is an arithmetic number, because the mean of its divisors is an integer number (106056106501045).

Almost surely, 2212112213002089 is an apocalyptic number.

It is an amenable number.

212112213002089 is a deficient number, since it is larger than the sum of its proper divisors (1).

212112213002089 is an equidigital number, since it uses as much as digits as its factorization.

212112213002089 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 34.

The spelling of 212112213002089 in words is "two hundred twelve trillion, one hundred twelve billion, two hundred thirteen million, two thousand, eighty-nine".