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212113117 is a prime number
BaseRepresentation
bin11001010010010…
…01011011011101
3112210010110111101
430221021123131
5413300104432
633014153101
75153634406
oct1451113335
9483113441
10212113117
11a98067a7
125b052791
1334c38928
14202569ad
151394d4e7
hexca496dd

212113117 has 2 divisors, whose sum is σ = 212113118. Its totient is φ = 212113116.

The previous prime is 212113081. The next prime is 212113141. The reversal of 212113117 is 711311212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 208686916 + 3426201 = 14446^2 + 1851^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212113117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 212113094 and 212113103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212113147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106056558 + 106056559.

It is an arithmetic number, because the mean of its divisors is an integer number (106056559).

Almost surely, 2212113117 is an apocalyptic number.

It is an amenable number.

212113117 is a deficient number, since it is larger than the sum of its proper divisors (1).

212113117 is an equidigital number, since it uses as much as digits as its factorization.

212113117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 84, while the sum is 19.

The square root of 212113117 is about 14564.1037142695. The cubic root of 212113117 is about 596.3792282310.

Adding to 212113117 its reverse (711311212), we get a palindrome (923424329).

The spelling of 212113117 in words is "two hundred twelve million, one hundred thirteen thousand, one hundred seventeen".