21211423041433 has 2 divisors, whose sum is σ = 21211423041434. Its totient is φ = 21211423041432.

The previous prime is 21211423041421. The next prime is 21211423041493. The reversal of 21211423041433 is 33414032411212.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 19348711246089 + 1862711795344 = 4398717^2 + 1364812^2 .

It is a cyclic number.

It is not a de Polignac number, because 21211423041433 - 2²¹ = 21211420944281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21211423041395 and 21211423041404.

It is not a weakly prime, because it can be changed into another prime (21211423041493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10605711520716 + 10605711520717.

It is an arithmetic number, because the mean of its divisors is an integer number (10605711520717).

Almost surely, 2^{21211423041433} is an apocalyptic number.

It is an amenable number.

21211423041433 is a deficient number, since it is larger than the sum of its proper divisors (1).

21211423041433 is an equidigital number, since it uses as much as digits as its factorization.

21211423041433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 21211423041433 its reverse (33414032411212), we get a palindrome (54625455452645).

The spelling of 21211423041433 in words is "twenty-one trillion, two hundred eleven billion, four hundred twenty-three million, forty-one thousand, four hundred thirty-three".