Base | Representation |
---|---|
bin | 1001101001010110011011… |
… | …10010010000000111010101 |
3 | 2210002211212211012002121222 |
4 | 10310223031302100013111 |
5 | 10240014134224311013 |
6 | 113040354142020125 |
7 | 4316342105436443 |
oct | 464531562200725 |
9 | 83084784162558 |
10 | 21212001010133 |
11 | 6838a6063571a |
12 | 2467040277645 |
13 | bab38acc7c6b |
14 | 534948587b93 |
15 | 26bb8d441508 |
hex | 134acdc901d5 |
21212001010133 has 2 divisors, whose sum is σ = 21212001010134. Its totient is φ = 21212001010132.
The previous prime is 21212001010111. The next prime is 21212001010147. The reversal of 21212001010133 is 33101010021212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14008536868804 + 7203464141329 = 3742798^2 + 2683927^2 .
It is a cyclic number.
It is not a de Polignac number, because 21212001010133 - 210 = 21212001009109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21212001010103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606000505066 + 10606000505067.
It is an arithmetic number, because the mean of its divisors is an integer number (10606000505067).
Almost surely, 221212001010133 is an apocalyptic number.
It is an amenable number.
21212001010133 is a deficient number, since it is larger than the sum of its proper divisors (1).
21212001010133 is an equidigital number, since it uses as much as digits as its factorization.
21212001010133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 21212001010133 its reverse (33101010021212), we get a palindrome (54313011031345).
The spelling of 21212001010133 in words is "twenty-one trillion, two hundred twelve billion, one million, ten thousand, one hundred thirty-three".
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