Base | Representation |
---|---|
bin | 1100010110001101011… |
… | …0000000001111011011 |
3 | 202021112000102001211222 |
4 | 3011203112000033123 |
5 | 11433410222010133 |
6 | 241240250042255 |
7 | 21216351120542 |
oct | 3054326001733 |
9 | 667460361758 |
10 | 212120110043 |
11 | 81a612aa276 |
12 | 3513a71938b |
13 | 17006318a1a |
14 | a3a3a47159 |
15 | 57b751ce98 |
hex | 31635803db |
212120110043 has 2 divisors, whose sum is σ = 212120110044. Its totient is φ = 212120110042.
The previous prime is 212120110001. The next prime is 212120110073. The reversal of 212120110043 is 340011021212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212120110043 is a prime.
It is not a weakly prime, because it can be changed into another prime (212120110073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106060055021 + 106060055022.
It is an arithmetic number, because the mean of its divisors is an integer number (106060055022).
Almost surely, 2212120110043 is an apocalyptic number.
212120110043 is a deficient number, since it is larger than the sum of its proper divisors (1).
212120110043 is an equidigital number, since it uses as much as digits as its factorization.
212120110043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 17.
Adding to 212120110043 its reverse (340011021212), we get a palindrome (552131131255).
The spelling of 212120110043 in words is "two hundred twelve billion, one hundred twenty million, one hundred ten thousand, forty-three".
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