Base | Representation |
---|---|
bin | 110000001110110010001100… |
… | …011001001010000111001111 |
3 | 1000211001200110211222112110001 |
4 | 300032302030121022013033 |
5 | 210300402231224020421 |
6 | 2031051332110225131 |
7 | 62452215603136366 |
oct | 6016621431120717 |
9 | 1024050424875401 |
10 | 212122200220111 |
11 | 6165257a0121a5 |
12 | 1b95a8537b51a7 |
13 | 91490649436cc |
14 | 3a54aaac427dd |
15 | 197cbba1c7691 |
hex | c0ec8c64a1cf |
212122200220111 has 2 divisors, whose sum is σ = 212122200220112. Its totient is φ = 212122200220110.
The previous prime is 212122200220079. The next prime is 212122200220141. The reversal of 212122200220111 is 111022002221212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212122200220111 - 25 = 212122200220079 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212122200220141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106061100110055 + 106061100110056.
It is an arithmetic number, because the mean of its divisors is an integer number (106061100110056).
Almost surely, 2212122200220111 is an apocalyptic number.
212122200220111 is a deficient number, since it is larger than the sum of its proper divisors (1).
212122200220111 is an equidigital number, since it uses as much as digits as its factorization.
212122200220111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 212122200220111 its reverse (111022002221212), we get a palindrome (323144202441323).
The spelling of 212122200220111 in words is "two hundred twelve trillion, one hundred twenty-two billion, two hundred million, two hundred twenty thousand, one hundred eleven".
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