Base | Representation |
---|---|
bin | 11110110111100011110… |
… | …101110001101101000111 |
3 | 21111210021221221020010011 |
4 | 132313203311301231013 |
5 | 234223300244332213 |
6 | 4302252421011051 |
7 | 306153224263561 |
oct | 36674365615507 |
9 | 7453257836104 |
10 | 2121241402183 |
11 | 74868251a822 |
12 | 2a313b553a87 |
13 | 1250559aaa37 |
14 | 74950a22331 |
15 | 3a2a1e4b03d |
hex | 1ede3d71b47 |
2121241402183 has 2 divisors, whose sum is σ = 2121241402184. Its totient is φ = 2121241402182.
The previous prime is 2121241402117. The next prime is 2121241402223. The reversal of 2121241402183 is 3812041421212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2121241402183 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2121241405183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060620701091 + 1060620701092.
It is an arithmetic number, because the mean of its divisors is an integer number (1060620701092).
Almost surely, 22121241402183 is an apocalyptic number.
2121241402183 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121241402183 is an equidigital number, since it uses as much as digits as its factorization.
2121241402183 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6144, while the sum is 31.
Adding to 2121241402183 its reverse (3812041421212), we get a palindrome (5933282823395).
The spelling of 2121241402183 in words is "two trillion, one hundred twenty-one billion, two hundred forty-one million, four hundred two thousand, one hundred eighty-three".
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