Base | Representation |
---|---|
bin | 1100010110001111110… |
… | …0001000010010010111 |
3 | 202021112201012211121222 |
4 | 3011203330020102113 |
5 | 11433420301320341 |
6 | 241241244200555 |
7 | 21216532065035 |
oct | 3054374102227 |
9 | 667481184558 |
10 | 212130104471 |
11 | 81a66a0622a |
12 | 35141b3915b |
13 | 17008407b9c |
14 | a3a50c9555 |
15 | 57b834444b |
hex | 3163f08497 |
212130104471 has 2 divisors, whose sum is σ = 212130104472. Its totient is φ = 212130104470.
The previous prime is 212130104447. The next prime is 212130104561. The reversal of 212130104471 is 174401031212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212130104471 - 210 = 212130103447 is a prime.
It is a super-3 number, since 3×2121301044713 (a number of 35 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 212130104471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212130184471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106065052235 + 106065052236.
It is an arithmetic number, because the mean of its divisors is an integer number (106065052236).
Almost surely, 2212130104471 is an apocalyptic number.
212130104471 is a deficient number, since it is larger than the sum of its proper divisors (1).
212130104471 is an equidigital number, since it uses as much as digits as its factorization.
212130104471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 212130104471 its reverse (174401031212), we get a palindrome (386531135683).
The spelling of 212130104471 in words is "two hundred twelve billion, one hundred thirty million, one hundred four thousand, four hundred seventy-one".
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