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2121321213007 = 19910659905593
BaseRepresentation
bin11110110111101000100…
…110001110110001001111
321111210111112010000222121
4132313220212032301033
5234223431212304012
64302304351353411
7306155213541313
oct36675046166117
97453445100877
102121321213007
11748713581887
122a3162222867
131250693a2c89
147495b479b43
153a2a8e63a07
hex1ede898ec4f

2121321213007 has 4 divisors (see below), whose sum is σ = 2131981118800. Its totient is φ = 2110661307216.

The previous prime is 2121321212993. The next prime is 2121321213017. The reversal of 2121321213007 is 7003121231212.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2121321213007 - 211 = 2121321210959 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2121321213017) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5329952598 + ... + 5329952995.

It is an arithmetic number, because the mean of its divisors is an integer number (532995279700).

Almost surely, 22121321213007 is an apocalyptic number.

2121321213007 is a deficient number, since it is larger than the sum of its proper divisors (10659905793).

2121321213007 is a wasteful number, since it uses less digits than its factorization.

2121321213007 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10659905792.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 2121321213007 its reverse (7003121231212), we get a palindrome (9124442444219).

The spelling of 2121321213007 in words is "two trillion, one hundred twenty-one billion, three hundred twenty-one million, two hundred thirteen thousand, seven".

Divisors: 1 199 10659905593 2121321213007