Base | Representation |
---|---|
bin | 11110110111101001111… |
… | …110110101011111101101 |
3 | 21111210120010211002211202 |
4 | 132313221332311133231 |
5 | 234224003134042201 |
6 | 4302310541255245 |
7 | 306155615141342 |
oct | 36675176653755 |
9 | 7453503732752 |
10 | 2121344440301 |
11 | 7487256a6899 |
12 | 2a3169b64525 |
13 | 125071146338 |
14 | 749605a47c9 |
15 | 3a2ab000c6b |
hex | 1ede9fb57ed |
2121344440301 has 2 divisors, whose sum is σ = 2121344440302. Its totient is φ = 2121344440300.
The previous prime is 2121344440253. The next prime is 2121344440307. The reversal of 2121344440301 is 1030444431212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1358693296900 + 762651143401 = 1165630^2 + 873299^2 .
It is a cyclic number.
It is not a de Polignac number, because 2121344440301 - 218 = 2121344178157 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2121344440307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060672220150 + 1060672220151.
It is an arithmetic number, because the mean of its divisors is an integer number (1060672220151).
Almost surely, 22121344440301 is an apocalyptic number.
It is an amenable number.
2121344440301 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121344440301 is an equidigital number, since it uses as much as digits as its factorization.
2121344440301 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 2121344440301 its reverse (1030444431212), we get a palindrome (3151788871513).
The spelling of 2121344440301 in words is "two trillion, one hundred twenty-one billion, three hundred forty-four million, four hundred forty thousand, three hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •