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212135117 is a prime number
BaseRepresentation
bin11001010010011…
…10110011001101
3112210011120200012
430221032303031
5413301310432
633014443005
75154055505
oct1451166315
9483146605
10212135117
11a9821287
125b063465
1334c4594c
1420260a05
1513954cb2
hexca4eccd

212135117 has 2 divisors, whose sum is σ = 212135118. Its totient is φ = 212135116.

The previous prime is 212135101. The next prime is 212135167. The reversal of 212135117 is 711531212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 169546441 + 42588676 = 13021^2 + 6526^2 .

It is a cyclic number.

It is not a de Polignac number, because 212135117 - 24 = 212135101 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 212135092 and 212135101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212135167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106067558 + 106067559.

It is an arithmetic number, because the mean of its divisors is an integer number (106067559).

Almost surely, 2212135117 is an apocalyptic number.

It is an amenable number.

212135117 is a deficient number, since it is larger than the sum of its proper divisors (1).

212135117 is an equidigital number, since it uses as much as digits as its factorization.

212135117 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 420, while the sum is 23.

The square root of 212135117 is about 14564.8589763169. The cubic root of 212135117 is about 596.3998459870.

Adding to 212135117 its reverse (711531212), we get a palindrome (923666329).

The spelling of 212135117 in words is "two hundred twelve million, one hundred thirty-five thousand, one hundred seventeen".