Base | Representation |
---|---|
bin | 1001101001011001010011… |
… | …01101101011011110000011 |
3 | 2210002222212022022022121201 |
4 | 10310230221231223132003 |
5 | 10240030314042042311 |
6 | 113041211155002031 |
7 | 4316425244013163 |
oct | 464545155533603 |
9 | 83088768268551 |
10 | 21213543315331 |
11 | 6839682190414 |
12 | 24673b0899317 |
13 | bab5756b00a3 |
14 | 534a533405a3 |
15 | 26bc2da459c1 |
hex | 134b29b6b783 |
21213543315331 has 2 divisors, whose sum is σ = 21213543315332. Its totient is φ = 21213543315330.
The previous prime is 21213543315319. The next prime is 21213543315457. The reversal of 21213543315331 is 13351334531212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21213543315331 - 215 = 21213543282563 is a prime.
It is a super-2 number, since 2×212135433153312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (21213543315301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606771657665 + 10606771657666.
It is an arithmetic number, because the mean of its divisors is an integer number (10606771657666).
Almost surely, 221213543315331 is an apocalyptic number.
21213543315331 is a deficient number, since it is larger than the sum of its proper divisors (1).
21213543315331 is an equidigital number, since it uses as much as digits as its factorization.
21213543315331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 97200, while the sum is 37.
Adding to 21213543315331 its reverse (13351334531212), we get a palindrome (34564877846543).
The spelling of 21213543315331 in words is "twenty-one trillion, two hundred thirteen billion, five hundred forty-three million, three hundred fifteen thousand, three hundred thirty-one".
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