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21213543315301 is a prime number
BaseRepresentation
bin1001101001011001010011…
…01101101011011101100101
32210002222212022022022120121
410310230221231223131211
510240030314042042201
6113041211155001541
74316425244013121
oct464545155533545
983088768268517
1021213543315301
116839682190397
1224673b08992b1
13bab5756b007c
14534a53340581
1526bc2da459a1
hex134b29b6b765

21213543315301 has 2 divisors, whose sum is σ = 21213543315302. Its totient is φ = 21213543315300.

The previous prime is 21213543315259. The next prime is 21213543315319. The reversal of 21213543315301 is 10351334531212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12354592308100 + 8858951007201 = 3514910^2 + 2976399^2 .

It is a cyclic number.

It is not a de Polignac number, because 21213543315301 - 211 = 21213543313253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21213543315331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606771657650 + 10606771657651.

It is an arithmetic number, because the mean of its divisors is an integer number (10606771657651).

Almost surely, 221213543315301 is an apocalyptic number.

It is an amenable number.

21213543315301 is a deficient number, since it is larger than the sum of its proper divisors (1).

21213543315301 is an equidigital number, since it uses as much as digits as its factorization.

21213543315301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 34.

Adding to 21213543315301 its reverse (10351334531212), we get a palindrome (31564877846513).

The spelling of 21213543315301 in words is "twenty-one trillion, two hundred thirteen billion, five hundred forty-three million, three hundred fifteen thousand, three hundred one".