Search a number
-
+
21214036533253 is a prime number
BaseRepresentation
bin1001101001011010001110…
…00111001010000000000101
32210010001010200101101102011
410310231013013022000011
510240032321323031003
6113041332134214221
74316443413212254
oct464550707120005
983101120341364
1021214036533253
116839905635333
122467509ab4371
13bab62392c205
14534a9ca4c79b
1526bc5bebe46d
hex134b471ca005

21214036533253 has 2 divisors, whose sum is σ = 21214036533254. Its totient is φ = 21214036533252.

The previous prime is 21214036533203. The next prime is 21214036533271. The reversal of 21214036533253 is 35233563041212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 21078401218884 + 135635314369 = 4591122^2 + 368287^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-21214036533253 is a prime.

It is a super-3 number, since 3×212140365332533 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21214036533203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10607018266626 + 10607018266627.

It is an arithmetic number, because the mean of its divisors is an integer number (10607018266627).

Almost surely, 221214036533253 is an apocalyptic number.

It is an amenable number.

21214036533253 is a deficient number, since it is larger than the sum of its proper divisors (1).

21214036533253 is an equidigital number, since it uses as much as digits as its factorization.

21214036533253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 388800, while the sum is 40.

Adding to 21214036533253 its reverse (35233563041212), we get a palindrome (56447599574465).

The spelling of 21214036533253 in words is "twenty-one trillion, two hundred fourteen billion, thirty-six million, five hundred thirty-three thousand, two hundred fifty-three".