21220000001113 has 2 divisors, whose sum is σ = 21220000001114. Its totient is φ = 21220000001112.

The previous prime is 21220000000951. The next prime is 21220000001119. The reversal of 21220000001113 is 31110000002212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13264367952784 + 7955632048329 = 3642028^2 + 2820573^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-21220000001113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21220000001093 and 21220000001102.

It is not a weakly prime, because it can be changed into another prime (21220000001119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10610000000556 + 10610000000557.

It is an arithmetic number, because the mean of its divisors is an integer number (10610000000557).

Almost surely, 2^{21220000001113} is an apocalyptic number.

It is an amenable number.

21220000001113 is a deficient number, since it is larger than the sum of its proper divisors (1).

21220000001113 is an equidigital number, since it uses as much as digits as its factorization.

21220000001113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 21220000001113 its reverse (31110000002212), we get a palindrome (52330000003325).

The spelling of 21220000001113 in words is "twenty-one trillion, two hundred twenty billion, one thousand, one hundred thirteen".