Base | Representation |
---|---|
bin | 110000001111111100100001… |
… | …000000101011111001111001 |
3 | 1000211100022110110000212201021 |
4 | 300033330201000223321321 |
5 | 210303204200233141213 |
6 | 2031152130541222441 |
7 | 62461042311561625 |
oct | 6017744100537171 |
9 | 1024308413025637 |
10 | 212202003021433 |
11 | 61683400679a67 |
12 | 1b972205561a21 |
13 | 9153741c622c9 |
14 | 3a588bb728185 |
15 | 197ecdb1e1d8d |
hex | c0ff2102be79 |
212202003021433 has 2 divisors, whose sum is σ = 212202003021434. Its totient is φ = 212202003021432.
The previous prime is 212202003021403. The next prime is 212202003021443. The reversal of 212202003021433 is 334120300202212.
212202003021433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 182036951299449 + 30165051721984 = 13492107^2 + 5492272^2 .
It is a cyclic number.
It is not a de Polignac number, because 212202003021433 - 233 = 212193413086841 is a prime.
It is a super-2 number, since 2×2122020030214332 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 212202003021398 and 212202003021407.
It is not a weakly prime, because it can be changed into another prime (212202003021403) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106101001510716 + 106101001510717.
It is an arithmetic number, because the mean of its divisors is an integer number (106101001510717).
Almost surely, 2212202003021433 is an apocalyptic number.
It is an amenable number.
212202003021433 is a deficient number, since it is larger than the sum of its proper divisors (1).
212202003021433 is an equidigital number, since it uses as much as digits as its factorization.
212202003021433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 212202003021433 its reverse (334120300202212), we get a palindrome (546322303223645).
The spelling of 212202003021433 in words is "two hundred twelve trillion, two hundred two billion, three million, twenty-one thousand, four hundred thirty-three".
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