Base | Representation |
---|---|
bin | 11110111000011000001… |
… | …110001000001111111011 |
3 | 21111212120012112211202022 |
4 | 132320120032020033323 |
5 | 234232100232414321 |
6 | 4302515532425055 |
7 | 306214055042063 |
oct | 36703016101773 |
9 | 7455505484668 |
10 | 2122120201211 |
11 | 748a9359150a |
12 | 2a334591818b |
13 | 125165a9046a |
14 | 749d56203a3 |
15 | 3a30418adab |
hex | 1ee183883fb |
2122120201211 has 2 divisors, whose sum is σ = 2122120201212. Its totient is φ = 2122120201210.
The previous prime is 2122120201199. The next prime is 2122120201237. The reversal of 2122120201211 is 1121020212212.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2122120201211 is a prime.
It is a super-4 number, since 4×21221202012114 (a number of 50 digits) contains 4444 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2122120201211.
It is not a weakly prime, because it can be changed into another prime (2122120201711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061060100605 + 1061060100606.
It is an arithmetic number, because the mean of its divisors is an integer number (1061060100606).
Almost surely, 22122120201211 is an apocalyptic number.
2122120201211 is a deficient number, since it is larger than the sum of its proper divisors (1).
2122120201211 is an equidigital number, since it uses as much as digits as its factorization.
2122120201211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64, while the sum is 17.
Adding to 2122120201211 its reverse (1121020212212), we get a palindrome (3243140413423).
The spelling of 2122120201211 in words is "two trillion, one hundred twenty-two billion, one hundred twenty million, two hundred one thousand, two hundred eleven".
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