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212214222879157 is a prime number
BaseRepresentation
bin110000010000000111111001…
…010111101111100110110101
31000211101111000001211222011101
4300100013321113233212311
5210303404212024113112
62031201511303210101
762461654162630162
oct6020077127574665
91024344001758141
10212214222879157
1161688601446a34
121b974655a46931
13915493b814855
143a5931a617069
1519802a3de0757
hexc101f95ef9b5

212214222879157 has 2 divisors, whose sum is σ = 212214222879158. Its totient is φ = 212214222879156.

The previous prime is 212214222879119. The next prime is 212214222879181. The reversal of 212214222879157 is 751978222412212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 127121881727556 + 85092341151601 = 11274834^2 + 9224551^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212214222879157 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 212214222879098 and 212214222879107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212214222879457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106107111439578 + 106107111439579.

It is an arithmetic number, because the mean of its divisors is an integer number (106107111439579).

Almost surely, 2212214222879157 is an apocalyptic number.

It is an amenable number.

212214222879157 is a deficient number, since it is larger than the sum of its proper divisors (1).

212214222879157 is an equidigital number, since it uses as much as digits as its factorization.

212214222879157 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4515840, while the sum is 55.

The spelling of 212214222879157 in words is "two hundred twelve trillion, two hundred fourteen billion, two hundred twenty-two million, eight hundred seventy-nine thousand, one hundred fifty-seven".