Base | Representation |
---|---|
bin | 110000010000010001010011… |
… | …110111101010100100100011 |
3 | 1000211102110002112022101010121 |
4 | 300100101103313222210203 |
5 | 210304040412232144141 |
6 | 2031210302314141111 |
7 | 62462462523433522 |
oct | 6020212367524443 |
9 | 1024373075271117 |
10 | 212224331131171 |
11 | 61691919279317 |
12 | 1b9765b7121797 |
13 | 915588ca74868 |
14 | 3a599d8cb84b9 |
15 | 19806965331d1 |
hex | c10453dea923 |
212224331131171 has 2 divisors, whose sum is σ = 212224331131172. Its totient is φ = 212224331131170.
The previous prime is 212224331131117. The next prime is 212224331131229. The reversal of 212224331131171 is 171131133422212.
Together with previous prime (212224331131117) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212224331131171 - 245 = 177039959042339 is a prime.
It is not a weakly prime, because it can be changed into another prime (212224331111171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106112165565585 + 106112165565586.
It is an arithmetic number, because the mean of its divisors is an integer number (106112165565586).
Almost surely, 2212224331131171 is an apocalyptic number.
212224331131171 is a deficient number, since it is larger than the sum of its proper divisors (1).
212224331131171 is an equidigital number, since it uses as much as digits as its factorization.
212224331131171 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 12096, while the sum is 34.
Adding to 212224331131171 its reverse (171131133422212), we get a palindrome (383355464553383).
The spelling of 212224331131171 in words is "two hundred twelve trillion, two hundred twenty-four billion, three hundred thirty-one million, one hundred thirty-one thousand, one hundred seventy-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •