Base | Representation |
---|---|
bin | 110000010000011010101000… |
… | …101001001011111000110111 |
3 | 1000211110101221022000221121112 |
4 | 300100122220221023320313 |
5 | 210304221413343132211 |
6 | 2031215040014305235 |
7 | 62463265606646546 |
oct | 6020325051137067 |
9 | 1024411838027545 |
10 | 212234343333431 |
11 | 61696096968041 |
12 | 1b9785301b821b |
13 | 91567c71450b3 |
14 | 3a5a2a88d615d |
15 | 1980a8050188b |
hex | c106a8a4be37 |
212234343333431 has 2 divisors, whose sum is σ = 212234343333432. Its totient is φ = 212234343333430.
The previous prime is 212234343333409. The next prime is 212234343333479. The reversal of 212234343333431 is 134333343432212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212234343333431 - 246 = 141865599155767 is a prime.
It is a super-2 number, since 2×2122343433334312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (212234343333491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106117171666715 + 106117171666716.
It is an arithmetic number, because the mean of its divisors is an integer number (106117171666716).
Almost surely, 2212234343333431 is an apocalyptic number.
212234343333431 is a deficient number, since it is larger than the sum of its proper divisors (1).
212234343333431 is an equidigital number, since it uses as much as digits as its factorization.
212234343333431 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1119744, while the sum is 41.
Adding to 212234343333431 its reverse (134333343432212), we get a palindrome (346567686765643).
The spelling of 212234343333431 in words is "two hundred twelve trillion, two hundred thirty-four billion, three hundred forty-three million, three hundred thirty-three thousand, four hundred thirty-one".
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