212243144003531 has 2 divisors, whose sum is σ = 212243144003532. Its totient is φ = 212243144003530.

The previous prime is 212243144003491. The next prime is 212243144003533. The reversal of 212243144003531 is 135300441342212.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 212243144003531 - 2²² = 212243139809227 is a prime.

It is a super-2 number, since 2×212243144003531² (a number of 29 digits) contains 22 as substring.

Together with 212243144003533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 212243144003491 and 212243144003500.

It is not a weakly prime, because it can be changed into another prime (212243144003533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106121572001765 + 106121572001766.

It is an arithmetic number, because the mean of its divisors is an integer number (106121572001766).

Almost surely, 2^{212243144003531} is an apocalyptic number.

212243144003531 is a deficient number, since it is larger than the sum of its proper divisors (1).

212243144003531 is an equidigital number, since it uses as much as digits as its factorization.

212243144003531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 212243144003531 its reverse (135300441342212), we get a palindrome (347543585345743).

The spelling of 212243144003531 in words is "two hundred twelve trillion, two hundred forty-three billion, one hundred forty-four million, three thousand, five hundred thirty-one".