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212295170081 is a prime number
BaseRepresentation
bin1100010110110111000…
…1110011100000100001
3202021222012211001002002
43011231301303200201
511434240030420311
6241305502133345
721223605112631
oct3055561634041
9667865731062
10212295170081
11820410a8495
1235189281255
1317033680247
14a3bcdb66c1
1557c7a9c93b
hex316dc73821

212295170081 has 2 divisors, whose sum is σ = 212295170082. Its totient is φ = 212295170080.

The previous prime is 212295170023. The next prime is 212295170089. The reversal of 212295170081 is 180071592212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 166293499681 + 46001670400 = 407791^2 + 214480^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212295170081 is a prime.

It is a super-2 number, since 2×2122951700812 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (212295170089) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106147585040 + 106147585041.

It is an arithmetic number, because the mean of its divisors is an integer number (106147585041).

Almost surely, 2212295170081 is an apocalyptic number.

It is an amenable number.

212295170081 is a deficient number, since it is larger than the sum of its proper divisors (1).

212295170081 is an equidigital number, since it uses as much as digits as its factorization.

212295170081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20160, while the sum is 38.

The spelling of 212295170081 in words is "two hundred twelve billion, two hundred ninety-five million, one hundred seventy thousand, eighty-one".