Base | Representation |
---|---|
bin | 1001101001111011110111… |
… | …10010010010001000011111 |
3 | 2210011202202120012211101211 |
4 | 10310331323302102020133 |
5 | 10240331320112420132 |
6 | 113053520411445251 |
7 | 4320653143202563 |
oct | 464757362221037 |
9 | 83152676184354 |
10 | 21232100123167 |
11 | 6846534aaa83a |
12 | 246ab0b456827 |
13 | bb024209575b |
14 | 5358d3aad6a3 |
15 | 26c467c39147 |
hex | 134f7bc9221f |
21232100123167 has 2 divisors, whose sum is σ = 21232100123168. Its totient is φ = 21232100123166.
The previous prime is 21232100123099. The next prime is 21232100123219. The reversal of 21232100123167 is 76132100123212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21232100123167 is a prime.
It is a super-3 number, since 3×212321001231673 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21232100103167) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10616050061583 + 10616050061584.
It is an arithmetic number, because the mean of its divisors is an integer number (10616050061584).
Almost surely, 221232100123167 is an apocalyptic number.
21232100123167 is a deficient number, since it is larger than the sum of its proper divisors (1).
21232100123167 is an equidigital number, since it uses as much as digits as its factorization.
21232100123167 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 31.
Adding to 21232100123167 its reverse (76132100123212), we get a palindrome (97364200246379).
The spelling of 21232100123167 in words is "twenty-one trillion, two hundred thirty-two billion, one hundred million, one hundred twenty-three thousand, one hundred sixty-seven".
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