Base | Representation |
---|---|
bin | 11110111001011111111… |
… | …010111100010101011011 |
3 | 21111222200001002000111212 |
4 | 132321133322330111123 |
5 | 234242031210144402 |
6 | 4303235143413335 |
7 | 306255632552504 |
oct | 36713772742533 |
9 | 7458601060455 |
10 | 2123323131227 |
11 | 749550609651 |
12 | 2a362075424b |
13 | 1252c806c47c |
14 | 74aab2b3bab |
15 | 3a374aa4952 |
hex | 1ee5febc55b |
2123323131227 has 2 divisors, whose sum is σ = 2123323131228. Its totient is φ = 2123323131226.
The previous prime is 2123323131221. The next prime is 2123323131263. The reversal of 2123323131227 is 7221313233212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2123323131227 - 212 = 2123323127131 is a prime.
It is a super-2 number, since 2×21233231312272 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2123323131193 and 2123323131202.
It is not a weakly prime, because it can be changed into another prime (2123323131221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061661565613 + 1061661565614.
It is an arithmetic number, because the mean of its divisors is an integer number (1061661565614).
Almost surely, 22123323131227 is an apocalyptic number.
2123323131227 is a deficient number, since it is larger than the sum of its proper divisors (1).
2123323131227 is an equidigital number, since it uses as much as digits as its factorization.
2123323131227 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18144, while the sum is 32.
Adding to 2123323131227 its reverse (7221313233212), we get a palindrome (9344636364439).
The spelling of 2123323131227 in words is "two trillion, one hundred twenty-three billion, three hundred twenty-three million, one hundred thirty-one thousand, two hundred twenty-seven".
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