Base | Representation |
---|---|
bin | 1100010111000000001… |
… | …1010011100010000011 |
3 | 202022001212120212010121 |
4 | 3011300003103202003 |
5 | 11434324311442011 |
6 | 241313343441111 |
7 | 21224550242143 |
oct | 3056003234203 |
9 | 668055525117 |
10 | 212333312131 |
11 | 8206068a146 |
12 | 35199bb6197 |
13 | 1703b5461c5 |
14 | a3c40a4923 |
15 | 57cb0d3e71 |
hex | 31700d3883 |
212333312131 has 2 divisors, whose sum is σ = 212333312132. Its totient is φ = 212333312130.
The previous prime is 212333312119. The next prime is 212333312207. The reversal of 212333312131 is 131213333212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212333312131 - 217 = 212333181059 is a prime.
It is a super-2 number, since 2×2123333121312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 212333312096 and 212333312105.
It is not a weakly prime, because it can be changed into another prime (212333312431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106166656065 + 106166656066.
It is an arithmetic number, because the mean of its divisors is an integer number (106166656066).
Almost surely, 2212333312131 is an apocalyptic number.
212333312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
212333312131 is an equidigital number, since it uses as much as digits as its factorization.
212333312131 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1944, while the sum is 25.
Adding to 212333312131 its reverse (131213333212), we get a palindrome (343546645343).
The spelling of 212333312131 in words is "two hundred twelve billion, three hundred thirty-three million, three hundred twelve thousand, one hundred thirty-one".
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