Base | Representation |
---|---|
bin | 11110111001100001110… |
… | …111001111001111000001 |
3 | 21111222202022101102100122 |
4 | 132321201313033033001 |
5 | 234242113030330442 |
6 | 4303242310030025 |
7 | 306256506530453 |
oct | 36714167171701 |
9 | 7458668342318 |
10 | 2123355714497 |
11 | 749567a43976 |
12 | 2a362b648315 |
13 | 125301a3a204 |
14 | 74ab17562d3 |
15 | 3a37788ddd2 |
hex | 1ee61dcf3c1 |
2123355714497 has 2 divisors, whose sum is σ = 2123355714498. Its totient is φ = 2123355714496.
The previous prime is 2123355714367. The next prime is 2123355714503. The reversal of 2123355714497 is 7944175533212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1912014155536 + 211341558961 = 1382756^2 + 459719^2 .
It is a cyclic number.
It is not a de Polignac number, because 2123355714497 - 218 = 2123355452353 is a prime.
It is not a weakly prime, because it can be changed into another prime (2123354714497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061677857248 + 1061677857249.
It is an arithmetic number, because the mean of its divisors is an integer number (1061677857249).
Almost surely, 22123355714497 is an apocalyptic number.
It is an amenable number.
2123355714497 is a deficient number, since it is larger than the sum of its proper divisors (1).
2123355714497 is an equidigital number, since it uses as much as digits as its factorization.
2123355714497 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6350400, while the sum is 53.
The spelling of 2123355714497 in words is "two trillion, one hundred twenty-three billion, three hundred fifty-five million, seven hundred fourteen thousand, four hundred ninety-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.440 sec. • engine limits •