Base | Representation |
---|---|
bin | 11110111010001000011… |
… | …001000011001100110011 |
3 | 21112001102100200211110021 |
4 | 132322020121003030303 |
5 | 234244424020043212 |
6 | 4303430400344311 |
7 | 306311516032255 |
oct | 36721031031463 |
9 | 7461370624407 |
10 | 2124002112307 |
11 | 749869902139 |
12 | 2a3790015097 |
13 | 1253a592c71a |
14 | 74b33539cd5 |
15 | 3a3b44c4307 |
hex | 1ee88643333 |
2124002112307 has 2 divisors, whose sum is σ = 2124002112308. Its totient is φ = 2124002112306.
The previous prime is 2124002112289. The next prime is 2124002112311. The reversal of 2124002112307 is 7032112004212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2124002112307 - 27 = 2124002112179 is a prime.
It is a super-2 number, since 2×21240021123072 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2124009112307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1062001056153 + 1062001056154.
It is an arithmetic number, because the mean of its divisors is an integer number (1062001056154).
Almost surely, 22124002112307 is an apocalyptic number.
2124002112307 is a deficient number, since it is larger than the sum of its proper divisors (1).
2124002112307 is an equidigital number, since it uses as much as digits as its factorization.
2124002112307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 2124002112307 its reverse (7032112004212), we get a palindrome (9156114116519).
The spelling of 2124002112307 in words is "two trillion, one hundred twenty-four billion, two million, one hundred twelve thousand, three hundred seven".
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