Base | Representation |
---|---|
bin | 10011110010000101… |
… | …100011111001111001 |
3 | 2000211100110121001221 |
4 | 103302011203321321 |
5 | 322000300210431 |
6 | 13431433112041 |
7 | 1351245014326 |
oct | 236205437171 |
9 | 60740417057 |
10 | 21241413241 |
11 | 9010251184 |
12 | 4149858621 |
13 | 200693bc99 |
14 | 1057115b4d |
15 | 844c37111 |
hex | 4f2163e79 |
21241413241 has 2 divisors, whose sum is σ = 21241413242. Its totient is φ = 21241413240.
The previous prime is 21241413233. The next prime is 21241413251. The reversal of 21241413241 is 14231414212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 20841253225 + 400160016 = 144365^2 + 20004^2 .
It is a cyclic number.
It is not a de Polignac number, because 21241413241 - 23 = 21241413233 is a prime.
It is not a weakly prime, because it can be changed into another prime (21241413211) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10620706620 + 10620706621.
It is an arithmetic number, because the mean of its divisors is an integer number (10620706621).
Almost surely, 221241413241 is an apocalyptic number.
It is an amenable number.
21241413241 is a deficient number, since it is larger than the sum of its proper divisors (1).
21241413241 is an equidigital number, since it uses as much as digits as its factorization.
21241413241 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1536, while the sum is 25.
Adding to 21241413241 its reverse (14231414212), we get a palindrome (35472827453).
The spelling of 21241413241 in words is "twenty-one billion, two hundred forty-one million, four hundred thirteen thousand, two hundred forty-one".
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