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21241433 is a prime number
BaseRepresentation
bin101000100000…
…1111001011001
31110222011202202
41101001321121
520414211213
62035135545
7345356243
oct121017131
943864682
1021241433
1110a99004
1271445b5
1345294c5
142b6d093
151ce8b58
hex1441e59

21241433 has 2 divisors, whose sum is σ = 21241434. Its totient is φ = 21241432.

The previous prime is 21241421. The next prime is 21241453. The reversal of 21241433 is 33414212.

It is an a-pointer prime, because the next prime (21241453) can be obtained adding 21241433 to its sum of digits (20).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 21187609 + 53824 = 4603^2 + 232^2 .

It is a cyclic number.

It is not a de Polignac number, because 21241433 - 220 = 20192857 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (21241453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10620716 + 10620717.

It is an arithmetic number, because the mean of its divisors is an integer number (10620717).

Almost surely, 221241433 is an apocalyptic number.

It is an amenable number.

21241433 is a deficient number, since it is larger than the sum of its proper divisors (1).

21241433 is an equidigital number, since it uses as much as digits as its factorization.

21241433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 576, while the sum is 20.

The square root of 21241433 is about 4608.8429133569. The cubic root of 21241433 is about 276.9456856759.

Adding to 21241433 its reverse (33414212), we get a palindrome (54655645).

The spelling of 21241433 in words is "twenty-one million, two hundred forty-one thousand, four hundred thirty-three".