2124384131 has 2 divisors, whose sum is σ = 2124384132. Its totient is φ = 2124384130.

The previous prime is 2124384079. The next prime is 2124384133. The reversal of 2124384131 is 1314834212.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-2124384131 is a prime.

It is a super-2 number, since 2×2124384131² = 9026015872089250322, which contains 22 as substring.

Together with 2124384133, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 2124384094 and 2124384103.

It is not a weakly prime, because it can be changed into another prime (2124384133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1062192065 + 1062192066.

It is an arithmetic number, because the mean of its divisors is an integer number (1062192066).

Almost surely, 2^2124384131 is an apocalyptic number.

2124384131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2124384131 is an equidigital number, since it uses as much as digits as its factorization.

2124384131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 4608, while the sum is 29.

The square root of 2124384131 is about 46091.0417651847. The cubic root of 2124384131 is about 1285.5165815542.

The spelling of 2124384131 in words is "two billion, one hundred twenty-four million, three hundred eighty-four thousand, one hundred thirty-one".