Base | Representation |
---|---|
bin | 1001101010011101101011… |
… | …10011101010111011101011 |
3 | 2210020111121200212121011211 |
4 | 10311032311303222323223 |
5 | 10241131004334401403 |
6 | 113110122012133551 |
7 | 4322165042616034 |
oct | 465166563527353 |
9 | 83214550777154 |
10 | 21250253434603 |
11 | 6853200086366 |
12 | 2472536a672b7 |
13 | bb1b75cb425b |
14 | 536736a07a8b |
15 | 26cb7b7c806d |
hex | 1353b5ceaeeb |
21250253434603 has 2 divisors, whose sum is σ = 21250253434604. Its totient is φ = 21250253434602.
The previous prime is 21250253434601. The next prime is 21250253434607. The reversal of 21250253434603 is 30643435205212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21250253434603 - 21 = 21250253434601 is a prime.
Together with 21250253434601, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (21250253434601) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10625126717301 + 10625126717302.
It is an arithmetic number, because the mean of its divisors is an integer number (10625126717302).
Almost surely, 221250253434603 is an apocalyptic number.
21250253434603 is a deficient number, since it is larger than the sum of its proper divisors (1).
21250253434603 is an equidigital number, since it uses as much as digits as its factorization.
21250253434603 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 518400, while the sum is 40.
Adding to 21250253434603 its reverse (30643435205212), we get a palindrome (51893688639815).
The spelling of 21250253434603 in words is "twenty-one trillion, two hundred fifty billion, two hundred fifty-three million, four hundred thirty-four thousand, six hundred three".
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