Base | Representation |
---|---|
bin | 10011110010101011… |
… | …101101000101101011 |
3 | 2000212001021121020121 |
4 | 103302223231011223 |
5 | 322010330143311 |
6 | 13432431304111 |
7 | 1351426011232 |
oct | 236253550553 |
9 | 60761247217 |
10 | 21251412331 |
11 | 9015960696 |
12 | 415107b037 |
13 | 2008a302c6 |
14 | 1058599b19 |
15 | 845a5eb71 |
hex | 4f2aed16b |
21251412331 has 2 divisors, whose sum is σ = 21251412332. Its totient is φ = 21251412330.
The previous prime is 21251412307. The next prime is 21251412337. The reversal of 21251412331 is 13321415212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21251412331 - 223 = 21243023723 is a prime.
It is a super-2 number, since 2×212514123312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21251412296 and 21251412305.
It is not a weakly prime, because it can be changed into another prime (21251412337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10625706165 + 10625706166.
It is an arithmetic number, because the mean of its divisors is an integer number (10625706166).
Almost surely, 221251412331 is an apocalyptic number.
21251412331 is a deficient number, since it is larger than the sum of its proper divisors (1).
21251412331 is an equidigital number, since it uses as much as digits as its factorization.
21251412331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1440, while the sum is 25.
Adding to 21251412331 its reverse (13321415212), we get a palindrome (34572827543).
The spelling of 21251412331 in words is "twenty-one billion, two hundred fifty-one million, four hundred twelve thousand, three hundred thirty-one".
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