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212580401413 is a prime number
BaseRepresentation
bin1100010111111011000…
…1111000000100000101
3202022201002112021220111
43011332301320010011
511440331040321123
6241354051433021
721233640412102
oct3057661700405
9668632467814
10212580401413
1182178104a66
12352488b5771
131707a7a9a93
14a408c23aa9
1557e2b4090d
hex317ec78105

212580401413 has 2 divisors, whose sum is σ = 212580401414. Its totient is φ = 212580401412.

The previous prime is 212580401359. The next prime is 212580401419. The reversal of 212580401413 is 314104085212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 204125047204 + 8455354209 = 451802^2 + 91953^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212580401413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (212580401419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106290200706 + 106290200707.

It is an arithmetic number, because the mean of its divisors is an integer number (106290200707).

Almost surely, 2212580401413 is an apocalyptic number.

It is an amenable number.

212580401413 is a deficient number, since it is larger than the sum of its proper divisors (1).

212580401413 is an equidigital number, since it uses as much as digits as its factorization.

212580401413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7680, while the sum is 31.

Adding to 212580401413 its reverse (314104085212), we get a palindrome (526684486625).

The spelling of 212580401413 in words is "two hundred twelve billion, five hundred eighty million, four hundred one thousand, four hundred thirteen".