Base | Representation |
---|---|
bin | 1001101011111010010101… |
… | …11011110001010000111011 |
3 | 2210102021000121211010011212 |
4 | 10311331022323301100323 |
5 | 10242434400000100011 |
6 | 113145030201513335 |
7 | 4325605566515363 |
oct | 465751273612073 |
9 | 83367017733155 |
10 | 21300000003131 |
11 | 6872308791613 |
12 | 24800baaa284b |
13 | bb67733ac715 |
14 | 538cd58079a3 |
15 | 26e0ddcac08b |
hex | 135f4aef143b |
21300000003131 has 2 divisors, whose sum is σ = 21300000003132. Its totient is φ = 21300000003130.
The previous prime is 21300000003127. The next prime is 21300000003133. The reversal of 21300000003131 is 13130000000312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21300000003131 - 22 = 21300000003127 is a prime.
It is a super-2 number, since 2×213000000031312 (a number of 27 digits) contains 22 as substring.
Together with 21300000003133, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (21300000003133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10650000001565 + 10650000001566.
It is an arithmetic number, because the mean of its divisors is an integer number (10650000001566).
Almost surely, 221300000003131 is an apocalyptic number.
21300000003131 is a deficient number, since it is larger than the sum of its proper divisors (1).
21300000003131 is an equidigital number, since it uses as much as digits as its factorization.
21300000003131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 14.
Adding to 21300000003131 its reverse (13130000000312), we get a palindrome (34430000003443).
The spelling of 21300000003131 in words is "twenty-one trillion, three hundred billion, three thousand, one hundred thirty-one".
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