Base | Representation |
---|---|
bin | 1001101011111100001110… |
… | …10100111110011000001111 |
3 | 2210102100122020102001112111 |
4 | 10311332013110332120033 |
5 | 10242443433342242112 |
6 | 113145314515044451 |
7 | 4325642652102562 |
oct | 465760724763017 |
9 | 83370566361474 |
10 | 21301013243407 |
11 | 6872788728a77 |
12 | 24803422a0727 |
13 | bb68a52a4291 |
14 | 538d902004d9 |
15 | 26e14cc065a7 |
hex | 135f8753e60f |
21301013243407 has 2 divisors, whose sum is σ = 21301013243408. Its totient is φ = 21301013243406.
The previous prime is 21301013243383. The next prime is 21301013243417. The reversal of 21301013243407 is 70434231010312.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21301013243407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21301013243417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10650506621703 + 10650506621704.
It is an arithmetic number, because the mean of its divisors is an integer number (10650506621704).
Almost surely, 221301013243407 is an apocalyptic number.
21301013243407 is a deficient number, since it is larger than the sum of its proper divisors (1).
21301013243407 is an equidigital number, since it uses as much as digits as its factorization.
21301013243407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 31.
Adding to 21301013243407 its reverse (70434231010312), we get a palindrome (91735244253719).
The spelling of 21301013243407 in words is "twenty-one trillion, three hundred one billion, thirteen million, two hundred forty-three thousand, four hundred seven".
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