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21301020233147 is a prime number
BaseRepresentation
bin1001101011111100001111…
…01111101000110110111011
32210102100122201120011122202
410311332013233220312323
510242443442134430042
6113145315324540415
74325643065364044
oct465760757506673
983370581504582
1021301020233147
116872791672516
1224803446b170b
13bb68a6880915
14538d910dd8cb
1526e14d637632
hex135f87be8dbb

21301020233147 has 2 divisors, whose sum is σ = 21301020233148. Its totient is φ = 21301020233146.

The previous prime is 21301020233093. The next prime is 21301020233149. The reversal of 21301020233147 is 74133202010312.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 21301020233147 - 234 = 21283840363963 is a prime.

Together with 21301020233149, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (21301020233149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10650510116573 + 10650510116574.

It is an arithmetic number, because the mean of its divisors is an integer number (10650510116574).

Almost surely, 221301020233147 is an apocalyptic number.

21301020233147 is a deficient number, since it is larger than the sum of its proper divisors (1).

21301020233147 is an equidigital number, since it uses as much as digits as its factorization.

21301020233147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 29.

Adding to 21301020233147 its reverse (74133202010312), we get a palindrome (95434222243459).

The spelling of 21301020233147 in words is "twenty-one trillion, three hundred one billion, twenty million, two hundred thirty-three thousand, one hundred forty-seven".