Base | Representation |
---|---|
bin | 11110111111110100101… |
… | …000100111110011100110 |
3 | 21112122012020121020000221 |
4 | 132333310220213303212 |
5 | 234344432423213110 |
6 | 4310321020154554 |
7 | 306616121421025 |
oct | 36776450476346 |
9 | 7478166536027 |
10 | 2130113101030 |
11 | 75141534a442 |
12 | 2a49b6698a5a |
13 | 125b3a9b8895 |
14 | 75152d9a8bc |
15 | 3a620c327da |
hex | 1eff4a27ce6 |
2130113101030 has 8 divisors (see below), whose sum is σ = 3834203581872. Its totient is φ = 852045240408.
The previous prime is 2130113101019. The next prime is 2130113101073. The reversal of 2130113101030 is 301013110312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-3 number, since 3×21301131010303 (a number of 38 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2130113100995 and 2130113101013.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 106505655042 + ... + 106505655061.
It is an arithmetic number, because the mean of its divisors is an integer number (479275447734).
Almost surely, 22130113101030 is an apocalyptic number.
2130113101030 is a deficient number, since it is larger than the sum of its proper divisors (1704090480842).
2130113101030 is a wasteful number, since it uses less digits than its factorization.
2130113101030 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 213011310110.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 2130113101030 its reverse (301013110312), we get a palindrome (2431126211342).
The spelling of 2130113101030 in words is "two trillion, one hundred thirty billion, one hundred thirteen million, one hundred one thousand, thirty".
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