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21301312099973 is a prime number
BaseRepresentation
bin1001101011111100110010…
…01001000001011010000101
32210102101102001202112200012
410311332121021001122011
510243000041344144343
6113145404312400005
74325653241250533
oct465763111013205
983371361675605
1021301312099973
1168729213a1374
1224804063a6005
13bb6922191799
14538dbbb97153
1526e16908b718
hex135f99241685

21301312099973 has 2 divisors, whose sum is σ = 21301312099974. Its totient is φ = 21301312099972.

The previous prime is 21301312099937. The next prime is 21301312100039. The reversal of 21301312099973 is 37999021310312.

Together with previous prime (21301312099937) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 20716634711809 + 584677388164 = 4551553^2 + 764642^2 .

It is a cyclic number.

It is not a de Polignac number, because 21301312099973 - 218 = 21301311837829 is a prime.

It is a super-2 number, since 2×213013120999732 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21301332099973) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10650656049986 + 10650656049987.

It is an arithmetic number, because the mean of its divisors is an integer number (10650656049987).

Almost surely, 221301312099973 is an apocalyptic number.

It is an amenable number.

21301312099973 is a deficient number, since it is larger than the sum of its proper divisors (1).

21301312099973 is an equidigital number, since it uses as much as digits as its factorization.

21301312099973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 551124, while the sum is 50.

The spelling of 21301312099973 in words is "twenty-one trillion, three hundred one billion, three hundred twelve million, ninety-nine thousand, nine hundred seventy-three".