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213020321117 is a prime number
BaseRepresentation
bin1100011001100100000…
…0000010010101011101
3202100211202022112021212
43012121000002111131
511442231200233432
6241505444434205
721250561565612
oct3063100022535
9670752275255
10213020321117
118238346616a
12353500a8965
131711a9874b6
14a44b41a509
15581b58c2b2
hex319900255d

213020321117 has 2 divisors, whose sum is σ = 213020321118. Its totient is φ = 213020321116.

The previous prime is 213020321021. The next prime is 213020321177. The reversal of 213020321117 is 711123020312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 189724709476 + 23295611641 = 435574^2 + 152629^2 .

It is a cyclic number.

It is not a de Polignac number, because 213020321117 - 212 = 213020317021 is a prime.

It is a super-2 number, since 2×2130203211172 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 213020321092 and 213020321101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213020321177) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106510160558 + 106510160559.

It is an arithmetic number, because the mean of its divisors is an integer number (106510160559).

Almost surely, 2213020321117 is an apocalyptic number.

It is an amenable number.

213020321117 is a deficient number, since it is larger than the sum of its proper divisors (1).

213020321117 is an equidigital number, since it uses as much as digits as its factorization.

213020321117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 213020321117 its reverse (711123020312), we get a palindrome (924143341429).

The spelling of 213020321117 in words is "two hundred thirteen billion, twenty million, three hundred twenty-one thousand, one hundred seventeen".