Base | Representation |
---|---|
bin | 1100011001100110010… |
… | …1111000001111010000 |
3 | 202100212102222112010112 |
4 | 3012121211320033100 |
5 | 11442241220204412 |
6 | 241510441220452 |
7 | 21251042113334 |
oct | 3063145701720 |
9 | 670772875115 |
10 | 213030241232 |
11 | 82389021306 |
12 | 35353491728 |
13 | 1711ca4b8a3 |
14 | a44c87d7c4 |
15 | 581c39b722 |
hex | 31999783d0 |
213030241232 has 10 divisors (see below), whose sum is σ = 412746092418. Its totient is φ = 106515120608.
The previous prime is 213030241217. The next prime is 213030241241. The reversal of 213030241232 is 232142030312.
It can be written as a sum of positive squares in only one way, i.e., 208596812176 + 4433429056 = 456724^2 + 66584^2 .
It is a super-3 number, since 3×2130302412323 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 213030241198 and 213030241207.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6657195023 + ... + 6657195054.
Almost surely, 2213030241232 is an apocalyptic number.
It is an amenable number.
213030241232 is a deficient number, since it is larger than the sum of its proper divisors (199715851186).
213030241232 is a wasteful number, since it uses less digits than its factorization.
213030241232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13314390085 (or 13314390079 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 213030241232 its reverse (232142030312), we get a palindrome (445172271544).
The spelling of 213030241232 in words is "two hundred thirteen billion, thirty million, two hundred forty-one thousand, two hundred thirty-two".
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