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21303142414 = 231733601171
BaseRepresentation
bin10011110101110001…
…000010100000001110
32000222122121202120121
4103311301002200032
5322112101024124
613441520135154
71352624502631
oct236561024016
960878552517
1021303142414
119042083224
1241664674ba
132016673018
1410613c3c18
1584a37c2e4
hex4f5c4280e

21303142414 has 8 divisors (see below), whose sum is σ = 32055518088. Its totient is φ = 10617969720.

The previous prime is 21303142411. The next prime is 21303142417. The reversal of 21303142414 is 41424130312.

It is an interprime number because it is at equal distance from previous prime (21303142411) and next prime (21303142417).

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-4 number, since 4×213031424144 (a number of 42 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21303142411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16799952 + ... + 16801219.

It is an arithmetic number, because the mean of its divisors is an integer number (4006939761).

Almost surely, 221303142414 is an apocalyptic number.

21303142414 is a deficient number, since it is larger than the sum of its proper divisors (10752375674).

21303142414 is a wasteful number, since it uses less digits than its factorization.

21303142414 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33601490.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 21303142414 its reverse (41424130312), we get a palindrome (62727272726).

The spelling of 21303142414 in words is "twenty-one billion, three hundred three million, one hundred forty-two thousand, four hundred fourteen".

Divisors: 1 2 317 634 33601171 67202342 10651571207 21303142414