Base | Representation |
---|---|
bin | 110000011100000001100001… |
… | …011101011111001000011011 |
3 | 1000221021122212021020112210121 |
4 | 300130001201131133020123 |
5 | 210410304030312014433 |
6 | 2033025320011454111 |
7 | 62605024606156312 |
oct | 6034014135371033 |
9 | 1027248767215717 |
10 | 213032013001243 |
11 | 61973407673767 |
12 | 1ba87046157337 |
13 | 91b3aa9389387 |
14 | 3a86b39575279 |
15 | 19966b8e2ec2d |
hex | c1c06175f21b |
213032013001243 has 2 divisors, whose sum is σ = 213032013001244. Its totient is φ = 213032013001242.
The previous prime is 213032013001217. The next prime is 213032013001261. The reversal of 213032013001243 is 342100310230312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213032013001243 - 221 = 213032010904091 is a prime.
It is not a weakly prime, because it can be changed into another prime (213032013001943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106516006500621 + 106516006500622.
It is an arithmetic number, because the mean of its divisors is an integer number (106516006500622).
Almost surely, 2213032013001243 is an apocalyptic number.
213032013001243 is a deficient number, since it is larger than the sum of its proper divisors (1).
213032013001243 is an equidigital number, since it uses as much as digits as its factorization.
213032013001243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 213032013001243 its reverse (342100310230312), we get a palindrome (555132323231555).
The spelling of 213032013001243 in words is "two hundred thirteen trillion, thirty-two billion, thirteen million, one thousand, two hundred forty-three".
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