Base | Representation |
---|---|
bin | 11111000000000001000… |
… | …101111100001100110011 |
3 | 21112122201210220011000021 |
4 | 133000001011330030303 |
5 | 234400344430111311 |
6 | 4310353444104311 |
7 | 306624240122236 |
oct | 37000105741463 |
9 | 7478653804007 |
10 | 2130322113331 |
11 | 751512328485 |
12 | 2a4a54695097 |
13 | 125b720a9cb9 |
14 | 75172a4741d |
15 | 3a63426c171 |
hex | 1f00117c333 |
2130322113331 has 2 divisors, whose sum is σ = 2130322113332. Its totient is φ = 2130322113330.
The previous prime is 2130322113299. The next prime is 2130322113383. The reversal of 2130322113331 is 1333112230312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2130322113331 - 25 = 2130322113299 is a prime.
It is a super-2 number, since 2×21303221133312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2130322113296 and 2130322113305.
It is not a weakly prime, because it can be changed into another prime (2130322113131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065161056665 + 1065161056666.
It is an arithmetic number, because the mean of its divisors is an integer number (1065161056666).
Almost surely, 22130322113331 is an apocalyptic number.
2130322113331 is a deficient number, since it is larger than the sum of its proper divisors (1).
2130322113331 is an equidigital number, since it uses as much as digits as its factorization.
2130322113331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 2130322113331 its reverse (1333112230312), we get a palindrome (3463434343643).
The spelling of 2130322113331 in words is "two trillion, one hundred thirty billion, three hundred twenty-two million, one hundred thirteen thousand, three hundred thirty-one".
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