Base | Representation |
---|---|
bin | 11111000000000001001… |
… | …010100101110000110011 |
3 | 21112122201220012001220121 |
4 | 133000001022211300303 |
5 | 234400400233112042 |
6 | 4310353530151111 |
7 | 306624253356523 |
oct | 37000112456063 |
9 | 7478656161817 |
10 | 2130323332147 |
11 | 751512a9016a |
12 | 2a4a54b82497 |
13 | 125b724159aa |
14 | 75172c83683 |
15 | 3a63440d367 |
hex | 1f0012a5c33 |
2130323332147 has 2 divisors, whose sum is σ = 2130323332148. Its totient is φ = 2130323332146.
The previous prime is 2130323332069. The next prime is 2130323332153. The reversal of 2130323332147 is 7412333230312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2130323332147 - 223 = 2130314943539 is a prime.
It is not a weakly prime, because it can be changed into another prime (2130323332177) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065161666073 + 1065161666074.
It is an arithmetic number, because the mean of its divisors is an integer number (1065161666074).
Almost surely, 22130323332147 is an apocalyptic number.
2130323332147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2130323332147 is an equidigital number, since it uses as much as digits as its factorization.
2130323332147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 34.
Adding to 2130323332147 its reverse (7412333230312), we get a palindrome (9542656562459).
The spelling of 2130323332147 in words is "two trillion, one hundred thirty billion, three hundred twenty-three million, three hundred thirty-two thousand, one hundred forty-seven".
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