Base | Representation |
---|---|
bin | 1001101100000000100100… |
… | …00101011110000111110111 |
3 | 2210102120122110220010022002 |
4 | 10312000102011132013313 |
5 | 10243013220322242101 |
6 | 113150341515325515 |
7 | 4326054440362505 |
oct | 466002205360767 |
9 | 83376573803262 |
10 | 21303341212151 |
11 | 6873772812389 |
12 | 2480891a5089b |
13 | bb6b8668c98b |
14 | 53913146d675 |
15 | 26e23729ed6b |
hex | 13601215e1f7 |
21303341212151 has 2 divisors, whose sum is σ = 21303341212152. Its totient is φ = 21303341212150.
The previous prime is 21303341212079. The next prime is 21303341212187. The reversal of 21303341212151 is 15121214330312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 21303341212151 - 210 = 21303341211127 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21303341214151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10651670606075 + 10651670606076.
It is an arithmetic number, because the mean of its divisors is an integer number (10651670606076).
Almost surely, 221303341212151 is an apocalyptic number.
21303341212151 is a deficient number, since it is larger than the sum of its proper divisors (1).
21303341212151 is an equidigital number, since it uses as much as digits as its factorization.
21303341212151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 21303341212151 its reverse (15121214330312), we get a palindrome (36424555542463).
The spelling of 21303341212151 in words is "twenty-one trillion, three hundred three billion, three hundred forty-one million, two hundred twelve thousand, one hundred fifty-one".
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