21303500401411 has 2 divisors, whose sum is σ = 21303500401412. Its totient is φ = 21303500401410.

The previous prime is 21303500401387. The next prime is 21303500401433. The reversal of 21303500401411 is 11410400530312.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-21303500401411 is a prime.

It is not a weakly prime, because it can be changed into another prime (21303500401111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10651750200705 + 10651750200706.

It is an arithmetic number, because the mean of its divisors is an integer number (10651750200706).

Almost surely, 2^{21303500401411} is an apocalyptic number.

21303500401411 is a deficient number, since it is larger than the sum of its proper divisors (1).

21303500401411 is an equidigital number, since it uses as much as digits as its factorization.

21303500401411 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 21303500401411 its reverse (11410400530312), we get a palindrome (32713900931723).

The spelling of 21303500401411 in words is "twenty-one trillion, three hundred three billion, five hundred million, four hundred one thousand, four hundred eleven".