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2130350040241 is a prime number
BaseRepresentation
bin11111000000000010110…
…000011110010010110001
321112122210202102222112021
4133000002300132102301
5234400424102241431
64310400322431441
7306625026364633
oct37000260362261
97478722388467
102130350040241
11751527072375
122a4a61b02581
13125b77b074b7
1475176636a53
153a636936b11
hex1f002c1e4b1

2130350040241 has 2 divisors, whose sum is σ = 2130350040242. Its totient is φ = 2130350040240.

The previous prime is 2130350040227. The next prime is 2130350040257. The reversal of 2130350040241 is 1420400530312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1111453605025 + 1018896435216 = 1054255^2 + 1009404^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2130350040241 is a prime.

It is not a weakly prime, because it can be changed into another prime (2130350340241) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065175020120 + 1065175020121.

It is an arithmetic number, because the mean of its divisors is an integer number (1065175020121).

Almost surely, 22130350040241 is an apocalyptic number.

It is an amenable number.

2130350040241 is a deficient number, since it is larger than the sum of its proper divisors (1).

2130350040241 is an equidigital number, since it uses as much as digits as its factorization.

2130350040241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 2130350040241 its reverse (1420400530312), we get a palindrome (3550750570553).

The spelling of 2130350040241 in words is "two trillion, one hundred thirty billion, three hundred fifty million, forty thousand, two hundred forty-one".