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2130362213151 = 31741771808101
BaseRepresentation
bin11111000000000011011…
…110111010001100011111
321112122211121100102121210
4133000003132322030133
5234400440211310101
64310401435355503
7306625235014314
oct37000336721437
97478747312553
102130362213151
11751532a27027
122a4a65bb2b93
13125b7a4aa0c3
14751780c4d0b
153a637a3d7d6
hex1f0037ba31f

2130362213151 has 8 divisors (see below), whose sum is σ = 3007570183344. Its totient is φ = 1336697859200.

The previous prime is 2130362213143. The next prime is 2130362213183. The reversal of 2130362213151 is 1513122630312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2130362213151 - 23 = 2130362213143 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2130362213191) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20885904000 + ... + 20885904101.

It is an arithmetic number, because the mean of its divisors is an integer number (375946272918).

Almost surely, 22130362213151 is an apocalyptic number.

2130362213151 is a deficient number, since it is larger than the sum of its proper divisors (877207970193).

2130362213151 is a wasteful number, since it uses less digits than its factorization.

2130362213151 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41771808121.

The product of its (nonzero) digits is 6480, while the sum is 30.

Adding to 2130362213151 its reverse (1513122630312), we get a palindrome (3643484843463).

The spelling of 2130362213151 in words is "two trillion, one hundred thirty billion, three hundred sixty-two million, two hundred thirteen thousand, one hundred fifty-one".

Divisors: 1 3 17 51 41771808101 125315424303 710120737717 2130362213151