Search a number
-
+
2130500400433 is a prime number
BaseRepresentation
bin11111000000001011101…
…110000011010100110001
321112200012020101001221021
4133000023232003110301
5234401231100303213
64310423253255441
7306631533414556
oct37001356032461
97480166331837
102130500400433
117515a3a30199
122a4aa4334581
13125ba0001322
147518c5b6a2d
153a644c37d8d
hex1f00bb83531

2130500400433 has 2 divisors, whose sum is σ = 2130500400434. Its totient is φ = 2130500400432.

The previous prime is 2130500400419. The next prime is 2130500400449. The reversal of 2130500400433 is 3340040050312.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2130499302129 + 1098304 = 1459623^2 + 1048^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2130500400433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2130500400398 and 2130500400407.

It is not a weakly prime, because it can be changed into another prime (2130500400233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065250200216 + 1065250200217.

It is an arithmetic number, because the mean of its divisors is an integer number (1065250200217).

Almost surely, 22130500400433 is an apocalyptic number.

It is an amenable number.

2130500400433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2130500400433 is an equidigital number, since it uses as much as digits as its factorization.

2130500400433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 25.

Adding to 2130500400433 its reverse (3340040050312), we get a palindrome (5470540450745).

The spelling of 2130500400433 in words is "two trillion, one hundred thirty billion, five hundred million, four hundred thousand, four hundred thirty-three".