Base | Representation |
---|---|
bin | 1100011001101011011… |
… | …1000011010010000100 |
3 | 202100220221000121021221 |
4 | 3012122313003102010 |
5 | 11442312142121012 |
6 | 241512521250124 |
7 | 21251421020053 |
oct | 3063267032204 |
9 | 670827017257 |
10 | 213051520132 |
11 | 8239a035480 |
12 | 3535a633944 |
13 | 1712428c159 |
14 | a45161c39a |
15 | 581e1a1507 |
hex | 319adc3484 |
213051520132 has 24 divisors (see below), whose sum is σ = 406849302720. Its totient is φ = 96814318560.
The previous prime is 213051520127. The next prime is 213051520139. The reversal of 213051520132 is 231025150312.
It is a junction number, because it is equal to n+sod(n) for n = 213051520097 and 213051520106.
It is not an unprimeable number, because it can be changed into a prime (213051520139) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 523663 + ... + 836854.
It is an arithmetic number, because the mean of its divisors is an integer number (16952054280).
Almost surely, 2213051520132 is an apocalyptic number.
213051520132 is a gapful number since it is divisible by the number (22) formed by its first and last digit.
It is an amenable number.
213051520132 is a deficient number, since it is larger than the sum of its proper divisors (193797782588).
213051520132 is a wasteful number, since it uses less digits than its factorization.
213051520132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1364091 (or 1364089 counting only the distinct ones).
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 213051520132 its reverse (231025150312), we get a palindrome (444076670444).
The spelling of 213051520132 in words is "two hundred thirteen billion, fifty-one million, five hundred twenty thousand, one hundred thirty-two".
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